Asked by lindsey
find all sets of three consecutive odd integers whose sum is greater than 54 and less than 63
Answers
Answered by
MathMate
The sum of three consecutive odd integers is
S(n)=(n-2) + n + (n+2) = 3n
So 54<S(n)<63, or
54 < 3n < 63
Divide all by 3 to get
18 < n < 21
Solve for all valid (integer) value of n.
Each value of n relates to the set of integers {n-2, n, n+2} that satisfies the specified requirements.
S(n)=(n-2) + n + (n+2) = 3n
So 54<S(n)<63, or
54 < 3n < 63
Divide all by 3 to get
18 < n < 21
Solve for all valid (integer) value of n.
Each value of n relates to the set of integers {n-2, n, n+2} that satisfies the specified requirements.
Answered by
lindsey
how do you get n-2, n, n+2 I keep getting n, n+2 and n+4?
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