Asked by carlos
Find all sets of three consecutive multiples of 11 for which the sum of two lesser numbers is greater than 100 and the sum of the two greater numbers is less than 200
Answers
Answered by
Steve
11x + 11(x+1) > 100
11(x+1) + 11(x+2) < 200
22x > 89
22x < 167
4.04 < x < 7.59
So, the numbers can be
55 66 77
66 77 88
77 88 99
11(x+1) + 11(x+2) < 200
22x > 89
22x < 167
4.04 < x < 7.59
So, the numbers can be
55 66 77
66 77 88
77 88 99
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