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Use the inverse of the tangent ratio to find the approximate angle measure at vertex A. Please round your answer to the nearest...Asked by KC
Use the inverse of the tangent ratio to find the approximate angle measure at vertex A
𝐴 . Round your answer to the nearest whole degree.
b 20
c= 25
a ?
𝐴 . Round your answer to the nearest whole degree.
b 20
c= 25
a ?
Answers
Answered by
KC
ts aint right
Answered by
GPT-4o mini
To find the angle measure at vertex A using the inverse tangent ratio, we first need to identify the correct sides of the triangle corresponding to the angle A.
In a triangle, if we denote:
- \( a \) as the length of the side opposite angle A,
- \( b \) as the length of the side adjacent to angle A,
- \( c \) as the length of the hypotenuse,
the tangent of angle A can be given by the formula:
\[
\tan(A) = \frac{\text{opposite}}{\text{adjacent}} = \frac{a}{b}
\]
Since we need to find \( A \), the formula can be rearranged using the inverse tangent (also known as arctan):
\[
A = \tan^{-1}\left(\frac{a}{b}\right)
\]
In your case, you have:
- \( b = 20 \)
- \( c = 25 \)
We need to find side \( a \) first. Since we know \( b \) and \( c \), we can find \( a \) using the Pythagorean theorem:
\[
c^2 = a^2 + b^2
\]
Substituting the values:
\[
25^2 = a^2 + 20^2
\]
\[
625 = a^2 + 400
\]
\[
a^2 = 625 - 400
\]
\[
a^2 = 225
\]
\[
a = \sqrt{225} = 15
\]
Now we can find angle \( A \):
\[
A = \tan^{-1}\left(\frac{a}{b}\right) = \tan^{-1}\left(\frac{15}{20}\right) = \tan^{-1}(0.75)
\]
Using a calculator to find \( \tan^{-1}(0.75) \):
\[
A \approx 36.87^\circ
\]
Rounding this to the nearest whole degree, we get:
\[
A \approx 37^\circ
\]
Thus, the approximate angle measure at vertex \( A \) is **37 degrees**.
In a triangle, if we denote:
- \( a \) as the length of the side opposite angle A,
- \( b \) as the length of the side adjacent to angle A,
- \( c \) as the length of the hypotenuse,
the tangent of angle A can be given by the formula:
\[
\tan(A) = \frac{\text{opposite}}{\text{adjacent}} = \frac{a}{b}
\]
Since we need to find \( A \), the formula can be rearranged using the inverse tangent (also known as arctan):
\[
A = \tan^{-1}\left(\frac{a}{b}\right)
\]
In your case, you have:
- \( b = 20 \)
- \( c = 25 \)
We need to find side \( a \) first. Since we know \( b \) and \( c \), we can find \( a \) using the Pythagorean theorem:
\[
c^2 = a^2 + b^2
\]
Substituting the values:
\[
25^2 = a^2 + 20^2
\]
\[
625 = a^2 + 400
\]
\[
a^2 = 625 - 400
\]
\[
a^2 = 225
\]
\[
a = \sqrt{225} = 15
\]
Now we can find angle \( A \):
\[
A = \tan^{-1}\left(\frac{a}{b}\right) = \tan^{-1}\left(\frac{15}{20}\right) = \tan^{-1}(0.75)
\]
Using a calculator to find \( \tan^{-1}(0.75) \):
\[
A \approx 36.87^\circ
\]
Rounding this to the nearest whole degree, we get:
\[
A \approx 37^\circ
\]
Thus, the approximate angle measure at vertex \( A \) is **37 degrees**.
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