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what is the inverse tangent of
(rad3/3)?
1 answer
30 degrees or pi/6 radians
a 30, 60, 90 triangle is in proportion to
1, sqrt 3, 2
so tan 30 = 1/sqrt 3 *(sqrt 3/sqrt 3) = sqrt 3/3
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cotx = - rad3 / 3
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sin(2 tan-1 7/24) (that is inverse tangent)
Draw a 7 24 25 right triangle. Label the angle whose tangent is 7/24. What is its
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