Asked by anna
what is the inverse tangent of
(rad3/3)?
(rad3/3)?
Answers
Answered by
Damon
30 degrees or pi/6 radians
a 30, 60, 90 triangle is in proportion to
1, sqrt 3, 2
so tan 30 = 1/sqrt 3 *(sqrt 3/sqrt 3) = sqrt 3/3
a 30, 60, 90 triangle is in proportion to
1, sqrt 3, 2
so tan 30 = 1/sqrt 3 *(sqrt 3/sqrt 3) = sqrt 3/3
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