Vf = 5000 g / (1 g/cm^3
Vs = 5000g / (1.033 g/cm^3)
we want Vf - Vs
The density of sea water is slightly higher than that of fresh water. The higher density is due to the fact that sea water contains salts such as sodium choride and magnesium chloride. Suppose you have a container that holds 5.00 kg of freshwater, which has a density of 1.00 g/cubic cm. If 5.00 kg of sea water with a density of 1.033 g/cubic cm is placed in a container of the same size, what is the volume of that space that is left unfilled? Not just an answer, I want to know how to do this, please!
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Oh, I have the same question on my homework. Hm, I don't know either.
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