Asked by Shaila
Wrtie a scalar equation given it's parametric equation.
x = 3-2s+2t
y = 1+3s+t
z = 5-s-2t
x = 3-2s+2t
y = 1+3s+t
z = 5-s-2t
Answers
Answered by
Reiny
Two direction vectors on the plane are (-2,3,-1) and (2,1,-2)
A normal to these is (5,6,8), their cross-product
so the plane has equation
5x + 6y + 8z = C
but (3,1,5) is a point on it, so
15 + 6 + 40 = C = 61
equation: 5x + 6y + 8z = 61
A normal to these is (5,6,8), their cross-product
so the plane has equation
5x + 6y + 8z = C
but (3,1,5) is a point on it, so
15 + 6 + 40 = C = 61
equation: 5x + 6y + 8z = 61
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