Asked by Calchelp
Determine the Scalar equation of the plane that passes through the point (2, -4, -3), and contains the vectors a = [-3, 5, -1] and b = [2, -4, 6]
Answers
Answered by
Reiny
We need the normal to both a and b which would be the cross-product a X b
I assume you know how to find the cross-product and that you got <13,8,1> in reduced form
So the equation of the plane is 13x + 8y + z = c
but (2,-4,-3) lies on it, so
26 - 32 - 3 = c = -9
Plane: 13x + 8y + z = -9
better check my arithmetic
I assume you know how to find the cross-product and that you got <13,8,1> in reduced form
So the equation of the plane is 13x + 8y + z = c
but (2,-4,-3) lies on it, so
26 - 32 - 3 = c = -9
Plane: 13x + 8y + z = -9
better check my arithmetic
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