Asked by Shaila
A 42kg girl jumps on a trampoline, after stretching to its bottom limit; the trampoline exerts an average upward force on the girl over a diplacement of 0.50m. During the time that the trampoline is pushing her up, se experiences an average acceleration of 65.0m/s^2. Her velocity at the moment that she leaves the trampoline is 9.4m/s[up]
a) What is the average force that the trampoline exerts on the girl?
b) How much high does she bounce?
a) What is the average force that the trampoline exerts on the girl?
b) How much high does she bounce?
Answers
Answered by
bobpursley
avgforce*distance=1/2 mass*velocity^2
solve for avgforce.
How high?
1/2 mass*velocity^2=mass*gh
or 1/2 velocity^2/g= height
solve for avgforce.
How high?
1/2 mass*velocity^2=mass*gh
or 1/2 velocity^2/g= height
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