Asked by Okiki

A crate of mass 42kg moving with a speed of 8m-1 on a rough horizontal floor is brought to rest after sliding a distance of 5m on the floor.calculate the coefficient of sliding friction between the crate and the floor

Answers

Answered by Okiki
Calculate the coefficient of sliding friction between the crate and the floor
Answered by henry2,
F = m*g = 42 * 9.8 = 411.6 N. = force of crate = normal force(Fn).
Fp = F*sin A = 411.6*sin 0 = 0 = Force parallel with plane.

V^2 = Vo^2 + 2a*d = 0.
8^2 + 2a*5 = 0,
a = -6.4 m/s^2.

Fp - u*Fn = M*a.
0 - u*411.6 = 42 * (-6.4),
u = 0.653. = Coefficient of friction.

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