Question
A crate, which has a mass of m= 45 kg, is being accelerated at 3.2m/s^-2 up an frictionless inclined plane, which meets the horizontal at an angle of 35 degrees, by a rope.
What is the magnitude of the normal force acting on the crate?
What is the tension acting in the rope?
What is the magnitude of the normal force acting on the crate?
What is the tension acting in the rope?
Answers
Net force= Tension + normal force + weigh
I used net force= ma.
I got Normal force= ma + mgCos(angle)
Normal force to be 505N.
Tension= ma + mgSin(angle)
= 396
Is this correct? or is the Net force = o.
I used net force= ma.
I got Normal force= ma + mgCos(angle)
Normal force to be 505N.
Tension= ma + mgSin(angle)
= 396
Is this correct? or is the Net force = o.
N=mgcosα
ma=T-mgsinα =>
T=m(a+gsinα)
ma=T-mgsinα =>
T=m(a+gsinα)
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