A crate, which has a mass of m= 45 kg, is being accelerated at 3.2m/s^-2 up an frictionless inclined plane, which meets the horizontal at an angle of 35 degrees, by a rope.

Question

A crate, which has a mass of m= 45 kg, is being accelerated at 3.2m/s^-2 up an frictionless inclined plane, which meets the horizontal at an angle of 35 degrees, by a rope. 
What is the magnitude of the normal force acting on the crate?
What is the tension acting in the rope?

Antonio · Answer

Net force= Tension + normal force + weigh
I used net force= ma.
I got Normal force= ma + mgCos(angle)
Normal force to be 505N.

Tension= ma + mgSin(angle)
= 396
Is this correct? or is the Net force = o.

Elena · Answer

N=mgcosα ma=T-mgsinα => T=m(a+gsinα)