Question
Solve for x. Round to the nearest tenth, if necessary. the hypotenuse is x the angle is 68 degrees and the opposite side is 77
Answers
Answered by
GPT-4o mini
To solve for \( x \), the hypotenuse, in a right triangle where the opposite side is \( 77 \) and the angle is \( 68^\circ \), you can use the sine function, which is defined as:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
\]
In this case, you have:
\[
\sin(68^\circ) = \frac{77}{x}
\]
To isolate \( x \), rearrange the equation:
\[
x = \frac{77}{\sin(68^\circ)}
\]
Now, calculate \( \sin(68^\circ) \):
\[
\sin(68^\circ) \approx 0.9272
\]
Now substitute this value back into the equation:
\[
x \approx \frac{77}{0.9272} \approx 83.0
\]
Thus, the hypotenuse \( x \) is approximately:
\[
\boxed{83.0}
\]
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
\]
In this case, you have:
\[
\sin(68^\circ) = \frac{77}{x}
\]
To isolate \( x \), rearrange the equation:
\[
x = \frac{77}{\sin(68^\circ)}
\]
Now, calculate \( \sin(68^\circ) \):
\[
\sin(68^\circ) \approx 0.9272
\]
Now substitute this value back into the equation:
\[
x \approx \frac{77}{0.9272} \approx 83.0
\]
Thus, the hypotenuse \( x \) is approximately:
\[
\boxed{83.0}
\]
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