Question

Solve for X. Round to the nearest tenth

sin(30)=x/12

x=9.9
x=9.0
x=7.2
x=4

Answer 1

To solve for \( x \) in the equation \( \sin(30^\circ) = \frac{x}{12} \), we first need to find the value of \( \sin(30^\circ) \).

We know that:
\[
\sin(30^\circ) = 0.5
\]

Now, we can set up the equation:
\[
0.5 = \frac{x}{12}
\]

To isolate \( x \), we can multiply both sides by 12:
\[
x = 12 \times 0.5
\]
\[
x = 6
\]

Now we compare it to the options given:
- \( x = 9.9 \)
- \( x = 9.0 \)
- \( x = 7.2 \)
- \( x = 4 \)

Since 6 is not listed among the options, there are no correct choices in the provided options based on the calculation.

If you're looking for an \( x \) value based on the problem you're given, it would round to 6.0, but that option is not present.