Question
Solve the system of equations.
–9x+y=12
2x+4y= −28 (1 point)
(, )
–9x+y=12
2x+4y= −28 (1 point)
(, )
Answers
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Answered by
GPT-4o mini
To solve the system of equations:
1. \(-9x + y = 12\) (Equation 1)
2. \(2x + 4y = -28\) (Equation 2)
Let's start by expressing \(y\) in terms of \(x\) using Equation 1:
\[
y = 9x + 12
\]
Now, we can substitute this expression for \(y\) into Equation 2:
\[
2x + 4(9x + 12) = -28
\]
Expanding the equation:
\[
2x + 36x + 48 = -28
\]
Combine like terms:
\[
38x + 48 = -28
\]
Now, subtract 48 from both sides:
\[
38x = -28 - 48
\]
\[
38x = -76
\]
Now, divide by 38:
\[
x = \frac{-76}{38} = -2
\]
Now, substitute back to find \(y\):
\[
y = 9(-2) + 12
\]
\[
y = -18 + 12 = -6
\]
Thus, the solution to the system of equations is:
\[
\boxed{(-2, -6)}
\]
1. \(-9x + y = 12\) (Equation 1)
2. \(2x + 4y = -28\) (Equation 2)
Let's start by expressing \(y\) in terms of \(x\) using Equation 1:
\[
y = 9x + 12
\]
Now, we can substitute this expression for \(y\) into Equation 2:
\[
2x + 4(9x + 12) = -28
\]
Expanding the equation:
\[
2x + 36x + 48 = -28
\]
Combine like terms:
\[
38x + 48 = -28
\]
Now, subtract 48 from both sides:
\[
38x = -28 - 48
\]
\[
38x = -76
\]
Now, divide by 38:
\[
x = \frac{-76}{38} = -2
\]
Now, substitute back to find \(y\):
\[
y = 9(-2) + 12
\]
\[
y = -18 + 12 = -6
\]
Thus, the solution to the system of equations is:
\[
\boxed{(-2, -6)}
\]
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