Question
What is the intermediate step in the form left parenthesis, x, plus, a, right parenthesis, squared, equals, b(x+a)
2
=b as a result of completing the square for the following equation?
minus, 3, x, squared, minus, 35, x, minus, 189, equals, 13, x
−3x
2
−35x−189=
13x
Answer
Attempt 1 out of 2
left parenthesis(
right parenthesis, squared, equals)
2
=
2
=b as a result of completing the square for the following equation?
minus, 3, x, squared, minus, 35, x, minus, 189, equals, 13, x
−3x
2
−35x−189=
13x
Answer
Attempt 1 out of 2
left parenthesis(
right parenthesis, squared, equals)
2
=
Answers
Answered by
GPT-4o mini
To solve the given equation by completing the square, we start with:
\[
-3x^2 - 35x - 189 = 13x
\]
First, let's rearrange the equation:
\[
-3x^2 - 35x - 13x - 189 = 0
\]
This simplifies to:
\[
-3x^2 - 48x - 189 = 0
\]
Next, we can divide the entire equation by -3 to simplify:
\[
x^2 + 16x + 63 = 0
\]
Now, let's move the constant term to the right side:
\[
x^2 + 16x = -63
\]
Now, we will complete the square for the left side. To do this, take half of the coefficient of \(x\) (which is 16), square it, and then add and subtract that value:
\[
\left(\frac{16}{2}\right)^2 = 8^2 = 64
\]
So, we add 64 to both sides of the equation:
\[
x^2 + 16x + 64 = -63 + 64
\]
This gives us:
\[
x^2 + 16x + 64 = 1
\]
Now, the left side can be factored as a perfect square:
\[
(x + 8)^2 = 1
\]
Thus, the intermediate step in the form \((x + a)^2 = b\) is:
\[
(x + 8)^2 = 1
\]
In your notation, where:
- \(a = 8\) and \(b = 1\), the final answer is:
\[
\text{Answer: } (x + 8)^2 = 1
\]
\[
-3x^2 - 35x - 189 = 13x
\]
First, let's rearrange the equation:
\[
-3x^2 - 35x - 13x - 189 = 0
\]
This simplifies to:
\[
-3x^2 - 48x - 189 = 0
\]
Next, we can divide the entire equation by -3 to simplify:
\[
x^2 + 16x + 63 = 0
\]
Now, let's move the constant term to the right side:
\[
x^2 + 16x = -63
\]
Now, we will complete the square for the left side. To do this, take half of the coefficient of \(x\) (which is 16), square it, and then add and subtract that value:
\[
\left(\frac{16}{2}\right)^2 = 8^2 = 64
\]
So, we add 64 to both sides of the equation:
\[
x^2 + 16x + 64 = -63 + 64
\]
This gives us:
\[
x^2 + 16x + 64 = 1
\]
Now, the left side can be factored as a perfect square:
\[
(x + 8)^2 = 1
\]
Thus, the intermediate step in the form \((x + a)^2 = b\) is:
\[
(x + 8)^2 = 1
\]
In your notation, where:
- \(a = 8\) and \(b = 1\), the final answer is:
\[
\text{Answer: } (x + 8)^2 = 1
\]
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