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A spring with k = 53 N/m hangs vertically next to the 15 cm mark on the ruler. If a 2.5 kg mass is now attached to the end of the spring, where will the end of the spring line up with the ruler marks
15 years ago

Answers

drwls
The added load is F = M g = 24.5 N
The spring will stretch by an amount
delta L = F/k = 0.46 m (46 cm)

That will increase the length to the 46 + 15 = 61 cm mark.
15 years ago

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