First make yourself a graph to see what the bounded region looks like. It looks to me like the region between two parabolas, one with a horizontal axis and one wth a vertical axis, with intersection points at (0,0) and (1,1). When this region gets rotated about an axis at x = -3, the volume of the solid formed is
Integral of pi*[(x1(y)+3)^2 - (x2(y)+3)^2]dy
from y = 0 to y=1
where x1(y) = sqrt y and
x2(y) = y^2
See if you agree. Then do the integration.
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=x^2 x=y^2 about the axis x=–3 ?
Having Trouble please help!!
1 answer
1 answer