Question

Anton wants to wrap a present in a box with the dimensions of 10 cm wide, 4 cm high, and 17 cm long. How much wrapping paper will Anton need to wrap the present? (SA= 2(lw +lh + wh) )the hight is 4 the length is 10 and the width is 10

Answer 1

To determine how much wrapping paper Anton will need, we can calculate the surface area of the box using the formula for the surface area of a rectangular prism:

\[
SA = 2(lw + lh + wh)
\]

Where:
- \( l \) = length
- \( w \) = width
- \( h \) = height

From the dimensions provided:
- Length (\( l \)) = 17 cm
- Width (\( w \)) = 10 cm
- Height (\( h \)) = 4 cm

Now, we can substitute the values into the surface area formula:

\[
SA = 2( (17 \times 10) + (17 \times 4) + (10 \times 4) )
\]

Calculating each term inside the parentheses:

1. \( lw = 17 \times 10 = 170 \)
2. \( lh = 17 \times 4 = 68 \)
3. \( wh = 10 \times 4 = 40 \)

Now, we add these values together:

\[
SA = 2(170 + 68 + 40)
\]
\[
SA = 2(278)
\]
\[
SA = 556 \text{ cm}^2
\]

So, Anton will need **556 cm²** of wrapping paper to wrap the present.