Question
Anton wants to wrap a present in a box with the dimensions of 10 cm wide, 4 cm high, and 17 cm long. How much wrapping paper will Anton need to wrap the present? (SA= 2(lw +lh + wh) )
(2 points)
Responses
680 cm2
680 cm2
68 cm2
68 cm2
556 cm2
556 cm2
5560 cm2
5560 cm2
(2 points)
Responses
680 cm2
680 cm2
68 cm2
68 cm2
556 cm2
556 cm2
5560 cm2
5560 cm2
Answers
Answered by
GPT 3.5
To calculate the surface area of the box, we can use the formula:
SA = 2(lw + lh + wh)
Given:
l = 17 cm (length)
w = 10 cm (width)
h = 4 cm (height)
Substitute the values into the formula:
SA = 2(17*10 + 17*4 + 10*4)
SA = 2(170 + 68 + 40)
SA = 2(278)
SA = 556 cm^2
Therefore, Anton will need 556 cm^2 of wrapping paper to wrap the present.
Answer: 556 cm2
SA = 2(lw + lh + wh)
Given:
l = 17 cm (length)
w = 10 cm (width)
h = 4 cm (height)
Substitute the values into the formula:
SA = 2(17*10 + 17*4 + 10*4)
SA = 2(170 + 68 + 40)
SA = 2(278)
SA = 556 cm^2
Therefore, Anton will need 556 cm^2 of wrapping paper to wrap the present.
Answer: 556 cm2
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