Question

(-31,3) and (25,9) slope line simify

Answer 1

To find the slope of the line that passes through the points \((-31, 3)\) and \((25, 9)\), you can use the formula for the slope \(m\):

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Here, \((x_1, y_1) = (-31, 3)\) and \((x_2, y_2) = (25, 9)\).

Plugging in the values:

\[
m = \frac{9 - 3}{25 - (-31)} = \frac{6}{25 + 31} = \frac{6}{56}
\]

Now, simplify \(\frac{6}{56}\):

\[
\frac{6 \div 2}{56 \div 2} = \frac{3}{28}
\]

So, the slope of the line that passes through the points \((-31, 3)\) and \((25, 9)\) is \(\frac{3}{28}\).