Question

Triangle MNO
is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?(1 point)
Responses

(5,−8)
left parenthesis 5 comma negative 8 right parenthesis

(−2,−11)
left parenthesis negative 2 comma negative 11 right parenthesis

(2,−1)
left parenthesis 2 comma negative 1 right parenthesis

(−2,−1)

Answer 1

To find the coordinates of point N' after the translation of triangle MNO, we start with the original coordinates of point N, which is (0, -6).

The translation moves the point up 5 units and left 2 units.

1. **Up 5 units**: This affects the y-coordinate. We take the original y-coordinate (-6) and add 5:
\[
-6 + 5 = -1
\]

2. **Left 2 units**: This affects the x-coordinate. We take the original x-coordinate (0) and subtract 2:
\[
0 - 2 = -2
\]

Combining these transformations, the new coordinates for point N' are:
\[
N' = (-2, -1)
\]

Thus, the correct response is:
\[
\boxed{(−2,−1)}
\]