Triangle MNO

is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?(1 point)
Responses

(5,−8)
left parenthesis 5 comma negative 8 right parenthesis

(−2,−11)
left parenthesis negative 2 comma negative 11 right parenthesis

(2,−1)
left parenthesis 2 comma negative 1 right parenthesis

(−2,−1)

1 answer

To find the coordinates of point N' after the translation of triangle MNO, we start with the original coordinates of point N, which is (0, -6).

The translation moves the point up 5 units and left 2 units.

  1. Up 5 units: This affects the y-coordinate. We take the original y-coordinate (-6) and add 5: \[ -6 + 5 = -1 \]

  2. Left 2 units: This affects the x-coordinate. We take the original x-coordinate (0) and subtract 2: \[ 0 - 2 = -2 \]

Combining these transformations, the new coordinates for point N' are: \[ N' = (-2, -1) \]

Thus, the correct response is: \[ \boxed{(−2,−1)} \]