Question

Use regrouping to find the sum as a decimal.

19
tens +
9
ones +
0.5
tenths +
0.12
hundredths

19
tens +
9
ones +
0.5
tenths +
(
0
tenths +
12
hundredths
)

​
tens +
​
ones +
​
tenths +
​
hundredths

13.56 + 6.06 =
​

Answer 1

To find the sum of \(13.56\) and \(6.06\) using regrouping, we can break it down into its place values: tens, ones, tenths, and hundredths.

We can align the numbers as follows:

```
13.56
+ 6.06
_______
```

Now, let's add from the rightmost column (hundredths) to the leftmost column (tens):

1. **Hundredths**: \(6 + 6 = 12\)
- Write down \(2\) and regroup \(1\) to the tenths column.

2. **Tenths**: \(5 + 0 + 1 = 6\) (the \(1\) came from regrouping the \(1\) from hundredths)
- Write down \(6\).

3. **Ones**: \(3 + 6 = 9\)
- Write down \(9\).

4. **Tens**: \(1 + 0 = 1\)
- Write down \(1\).

Now, combining these gives us:

```
19.62
```

Thus, the sum of \(13.56\) and \(6.06\) is **19.62**.