Question

Use regrouping to find the sum as a decimal.

46
tens +
13
ones +
9
tenths +
0
hundredths

46
tens +
13
ones +
(
0
ones +
9
tenths
)
+
0
hundredths

​
tens +
​
ones +
​
tenths +
​
hundredths

Answer 1

To find the sum using regrouping, we can break down the numbers into their respective place values.

Let's start with the numbers provided:

- **46 tens** = 460
- **13 ones** = 13
- **9 tenths** = 0.9 (which represents 9/10)
- **0 hundredths** = 0.00

Now we can rewrite the numbers fully represented in decimal form:

1. **Convert to Decimal**:
- 46 tens = \( 460.00 \)
- 13 ones = \( 13.00 \)
- 9 tenths = \( 0.90 \)
- 0 hundredths = \( 0.00 \)

Now, add these values together:

\[
460.00 + 13.00 + 0.90 + 0.00
\]

**Performing the Addition**:

- First, add the whole numbers (without the decimal):
\[
460 + 13 = 473
\]

- Now, include the decimal part:
\[
473 + 0.90 = 473.90
\]

So, the final sum as a decimal is:

\[
\text{Final Sum} = 473.90
\]

### Summary:
The total sum using regrouping is **473.90**.