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PART ONE:

Solve for y
.

−20=−5+3y


(1 point)
y =

Question 2
PART TWO:

Solve for x
.

5x+8+x=32

(1 point)
x =

1 answer

PART ONE:

To solve for \( y \) in the equation \( -20 = -5 + 3y \):

  1. Start by isolating \( 3y \): \[ -20 + 5 = 3y \] \[ -15 = 3y \]

  2. Now, divide both sides by 3: \[ y = \frac{-15}{3} \] \[ y = -5 \]

So, \( y = -5 \).

PART TWO:

To solve for \( x \) in the equation \( 5x + 8 + x = 32 \):

  1. Combine like terms (\( 5x \) and \( x \)): \[ 6x + 8 = 32 \]

  2. Now, isolate \( 6x \) by subtracting 8 from both sides: \[ 6x = 32 - 8 \] \[ 6x = 24 \]

  3. Finally, divide by 6: \[ x = \frac{24}{6} \] \[ x = 4 \]

So, \( x = 4 \).