Question

PART ONE:

Solve for y
.

−20=−5+3y


(1 point)
y =

Question 2
PART TWO:

Solve for x
.

5x+8+x=32

(1 point)
x =

Answer 1

PART ONE:

To solve for \( y \) in the equation \( -20 = -5 + 3y \):

1. Start by isolating \( 3y \):
\[
-20 + 5 = 3y
\]
\[
-15 = 3y
\]

2. Now, divide both sides by 3:
\[
y = \frac{-15}{3}
\]
\[
y = -5
\]

So, \( y = -5 \).

---

PART TWO:

To solve for \( x \) in the equation \( 5x + 8 + x = 32 \):

1. Combine like terms (\( 5x \) and \( x \)):
\[
6x + 8 = 32
\]

2. Now, isolate \( 6x \) by subtracting 8 from both sides:
\[
6x = 32 - 8
\]
\[
6x = 24
\]

3. Finally, divide by 6:
\[
x = \frac{24}{6}
\]
\[
x = 4
\]

So, \( x = 4 \).