PART ONE:

Solve for x
,

7(4x−15)=63


(1 point)
x =

Question 2
PART TWO:

Solve for y
.

−2(3y−15)−25=35

(1 point)
y =

1 answer

Let's solve each part step by step.

PART ONE:

Given the equation:

\[ 7(4x - 15) = 63 \]

  1. Start by dividing both sides by 7:

\[ 4x - 15 = 9 \quad (\text{since } 63 \div 7 = 9) \]

  1. Next, add 15 to both sides:

\[ 4x = 9 + 15 \]

\[ 4x = 24 \]

  1. Now, divide both sides by 4:

\[ x = \frac{24}{4} \]

\[ x = 6 \]

Final answer for Part One:

\[ \boxed{6} \]


PART TWO:

Given the equation:

\[ -2(3y - 15) - 25 = 35 \]

  1. Distribute the -2:

\[ -6y + 30 - 25 = 35 \]

  1. Combine like terms:

\[ -6y + 5 = 35 \]

  1. Subtract 5 from both sides:

\[ -6y = 35 - 5 \]

\[ -6y = 30 \]

  1. Finally, divide by -6:

\[ y = \frac{30}{-6} \]

\[ y = -5 \]

Final answer for Part Two:

\[ \boxed{-5} \]