Question

PART ONE:

Solve for x
,

7(4x−15)=63


(1 point)
x =

Question 2
PART TWO:

Solve for y
.

−2(3y−15)−25=35

(1 point)
y =

Answer 1

Let's solve each part step by step.

**PART ONE:**

Given the equation:

\[
7(4x - 15) = 63
\]

1. Start by dividing both sides by 7:

\[
4x - 15 = 9 \quad (\text{since } 63 \div 7 = 9)
\]

2. Next, add 15 to both sides:

\[
4x = 9 + 15
\]

\[
4x = 24
\]

3. Now, divide both sides by 4:

\[
x = \frac{24}{4}
\]

\[
x = 6
\]

**Final answer for Part One:**

\[
\boxed{6}
\]

---

**PART TWO:**

Given the equation:

\[
-2(3y - 15) - 25 = 35
\]

1. Distribute the -2:

\[
-6y + 30 - 25 = 35
\]

2. Combine like terms:

\[
-6y + 5 = 35
\]

3. Subtract 5 from both sides:

\[
-6y = 35 - 5
\]

\[
-6y = 30
\]

4. Finally, divide by -6:

\[
y = \frac{30}{-6}
\]

\[
y = -5
\]

**Final answer for Part Two:**

\[
\boxed{-5}
\]