Let's solve each part step by step.
PART ONE:
Given the equation:
\[ 7(4x - 15) = 63 \]
- Start by dividing both sides by 7:
\[ 4x - 15 = 9 \quad (\text{since } 63 \div 7 = 9) \]
- Next, add 15 to both sides:
\[ 4x = 9 + 15 \]
\[ 4x = 24 \]
- Now, divide both sides by 4:
\[ x = \frac{24}{4} \]
\[ x = 6 \]
Final answer for Part One:
\[ \boxed{6} \]
PART TWO:
Given the equation:
\[ -2(3y - 15) - 25 = 35 \]
- Distribute the -2:
\[ -6y + 30 - 25 = 35 \]
- Combine like terms:
\[ -6y + 5 = 35 \]
- Subtract 5 from both sides:
\[ -6y = 35 - 5 \]
\[ -6y = 30 \]
- Finally, divide by -6:
\[ y = \frac{30}{-6} \]
\[ y = -5 \]
Final answer for Part Two:
\[ \boxed{-5} \]