Question

The diagram features a plane, depicted as a parallelogram. There are five labeled points on the plane: Z, X, T, V, and L. From these points, five vectors originate: Vector S starts at point L and points upwards and to the left. Vector T starts at point T and points to the right. Vector V starts at point V and points to the right. Vector X starts at point X and points downwards and to the right. Vector Z starts at point Z and points to the left. This diagram likely demonstrates the relationships between vectors and the plane, such as vector addition, vector components, or other geometric concepts.
Given the image, identify the intersection of ST←→
and LX←→
.(1 point)

A. S
B. V
C. T
D. L

Answer 1

To determine the intersection of the lines described by vectors \( \overleftrightarrow{ST} \) and \( \overleftrightarrow{LX} \), we can analyze the vectors derived from their starting points and directions.

1. Vector \( S \) originates from point \( L \) and points upwards and to the left.
2. Vector \( T \) originates from point \( T \) and points to the right.
3. Vector \( V \) originates from point \( V \) and points to the right.
4. Vector \( X \) originates from point \( X \) and points downwards and to the right.
5. Vector \( Z \) originates from point \( Z \) and points to the left.

Given that \( \overleftrightarrow{ST} \) connects points along the direction of vector \( S \) (from \( L \)) to \( T \), and \( \overleftrightarrow{LX} \) connects points along the direction of vector \( L \) (from \( L \)) to \( X \) (downwards and to the right), we need to visualize where these two lines intersect or if they meet.

Since both lines originate from point \( L \), they converge there, making point \( L \) their intersection point.

Thus, the answer to the question regarding the intersection of \( \overleftrightarrow{ST} \) and \( \overleftrightarrow{LX} \) is:

**D. L**