Asked by Ashley
which of the following equations is the one represented by this experiment? Justify your answer by comparing the moles of iron consumed(Fe 0.139/0.0419= 3.32) and the moles of copper produced(Cu 0.0419/ 0.0419 =1) to the coefficients in the equation of your choice.
Fe + CuCl2 --> FeCl2 + Cu OR 2 Fe + 3 CuCl2 ---> 2 FeCl3 + 3 Cu.
I chose the first equation but don't know why and don't know how to compare these moles of iron consumed to copper produced? How do I do that? What formula do I use?
Fe + CuCl2 --> FeCl2 + Cu OR 2 Fe + 3 CuCl2 ---> 2 FeCl3 + 3 Cu.
I chose the first equation but don't know why and don't know how to compare these moles of iron consumed to copper produced? How do I do that? What formula do I use?
Answers
Answered by
bobpursley
The first equation for each mole of iron consumed yields on mole of copper, or ration=1
The second equation has 3moles copper for each mole of iron.
Ratio= 3
From your data, you got 3.32/1=3
so which equation matches your data?
The second equation has 3moles copper for each mole of iron.
Ratio= 3
From your data, you got 3.32/1=3
so which equation matches your data?
Answered by
Henry
I've done the exact same experiment. Double check your moles of iron. Your copper is correct, but the iron seems wrong.
It should be a ratio of 1:1, while the Copper was a ratio of 1.04:1, or 1:1. You should have got 2.25 g of Iron consumed, with the molar mass of 55.845g/mol, so therefore Iron should be 0.0403 moles of Fe.
So, therefore since there's a ratio of 1 mole of Iron and Copper, which one do you think it would be? :)
It should be a ratio of 1:1, while the Copper was a ratio of 1.04:1, or 1:1. You should have got 2.25 g of Iron consumed, with the molar mass of 55.845g/mol, so therefore Iron should be 0.0403 moles of Fe.
So, therefore since there's a ratio of 1 mole of Iron and Copper, which one do you think it would be? :)
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