Asked by Tammy

A wooden block slides directly down an incline plane at a constant velocity of 6 m/s. What is the coefficient of kinetic friction if the plane makes an angle of 30 degrees with the horizontal?

the coefficient of kinetic friction = force of kinetic friction/normal force. How would i solve this problem? i am only given velocity and the angle. I can't figure out the equation for this problem. Thanks in advance for your help.
Answered by bobpursley
The downward force along the plane is mg*sin30. If the block is at constant velocity, then this must equal friction force.Friction force is mu*mg*cos30

mu*mg*cos30=mgsin30

mu= tan 30
Answered by Anonymous
An object of mass 20kg slides down an inclined plane at an angle of 30degrees to the horizontal. The coefficient of static friction is what?
Answered by Akansha
10 ms
There are no AI answers yet. The ability to request AI answers is coming soon!