Asked by angela
In an iodometric titration, excess potassium iodide solution (KI) is added to the sample.Analyte such as chlorine liberates iodine from KI under acidic condition. Liberated iodine is titrated against standard sodium thiosulphate.
The concentration of analyte in the sample is given as
mg analyte/L
= (mL sodium thiosulphate x normality of sodium thiosulphate x milliequivalent weight of analyte) / mL of sample
Why do we need to multiply by normality of sodium thiosulphate?
The concentration of analyte in the sample is given as
mg analyte/L
= (mL sodium thiosulphate x normality of sodium thiosulphate x milliequivalent weight of analyte) / mL of sample
Why do we need to multiply by normality of sodium thiosulphate?
Answers
Answered by
DrBob222
mL Na2S2O3 x N Na2S2O3 = # milliequivalents.
Then #milliequivalents x milliequivalent weight = grams.
Then #milliequivalents x milliequivalent weight = grams.
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