Question
The booster club is selling refreshments. The following system of linear equations models the concession stand prices. Let h represent the cost of a hot dog and s represent the cost of the soda. Write the answers in decimal form. Solve the system of linear equations.
4h+4s=10
7h+5s=15
(1 point)
h=$
s=$
4h+4s=10
7h+5s=15
(1 point)
h=$
s=$
Answers
GPT-4o mini
To solve the system of equations:
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
First, we can simplify the first equation. Divide the entire equation by 4:
\[
h + s = 2.5 \quad \text{(Equation 1)}
\]
Now we can express \( s \) in terms of \( h \):
\[
s = 2.5 - h \quad \text{(Equation 3)}
\]
Next, we substitute Equation 3 into the second equation:
\[
7h + 5(2.5 - h) = 15
\]
Distribute the 5:
\[
7h + 12.5 - 5h = 15
\]
Combine like terms:
\[
2h + 12.5 = 15
\]
Now, isolate \( h \):
\[
2h = 15 - 12.5
\]
\[
2h = 2.5
\]
\[
h = 1.25
\]
Now, substitute \( h = 1.25 \) back into Equation 3 to find \( s \):
\[
s = 2.5 - 1.25
\]
\[
s = 1.25
\]
Thus, the final answer is:
\[
h = 1.25
\]
\[
s = 1.25
\]
So, in decimal form:
- \( h = \$1.25 \)
- \( s = \$1.25 \)
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
First, we can simplify the first equation. Divide the entire equation by 4:
\[
h + s = 2.5 \quad \text{(Equation 1)}
\]
Now we can express \( s \) in terms of \( h \):
\[
s = 2.5 - h \quad \text{(Equation 3)}
\]
Next, we substitute Equation 3 into the second equation:
\[
7h + 5(2.5 - h) = 15
\]
Distribute the 5:
\[
7h + 12.5 - 5h = 15
\]
Combine like terms:
\[
2h + 12.5 = 15
\]
Now, isolate \( h \):
\[
2h = 15 - 12.5
\]
\[
2h = 2.5
\]
\[
h = 1.25
\]
Now, substitute \( h = 1.25 \) back into Equation 3 to find \( s \):
\[
s = 2.5 - 1.25
\]
\[
s = 1.25
\]
Thus, the final answer is:
\[
h = 1.25
\]
\[
s = 1.25
\]
So, in decimal form:
- \( h = \$1.25 \)
- \( s = \$1.25 \)