To solve the system of linear equations:
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Equations: \[ 4h + 4s = 10 \quad \text{(Equation 1)} \] \[ 7h + 5s = 15 \quad \text{(Equation 2)} \]
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Simplify Equation 1: Dividing the entire first equation by 4: \[ h + s = 2.5 \quad \text{(Equation 1 simplified)} \]
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Express one variable in terms of the other from Equation 1: \[ s = 2.5 - h \]
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Substitute into Equation 2: Substitute \( s \) into Equation 2: \[ 7h + 5(2.5 - h) = 15 \] Simplifying: \[ 7h + 12.5 - 5h = 15 \] \[ 2h + 12.5 = 15 \] \[ 2h = 15 - 12.5 \] \[ 2h = 2.5 \] \[ h = 1.25 \]
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Substitute \( h \) back to find \( s \): Using \( h = 1.25 \) in the simplified Equation 1: \[ s = 2.5 - 1.25 = 1.25 \]
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Final Answer: \[ h = 1.25 \] \[ s = 1.25 \]
Thus, the costs are: \[ h = $1.25 \] \[ s = $1.25 \]