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The coordinates of the center of a circle with equation (x − 6)2 + (y + 3)2 = 72 are:
15 years ago

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Answered by Henry
(x - h)^2 + (y - k)^2 = r^2 C(h , k) = C(6 , -3).
15 years ago
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The coordinates of the center of a circle with equation (x − 6)2 + (y + 3)2 = 72 are:

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