Question
The diameter of the cracker shown is 35 millimeters.
Which measurement is closest to the area of the cracker in square millimeters?
Responses
A 109.9 mm²109.9 mm²
B 54.95 mm²54.95 mm²
C 961.625 mm²961.625 mm²
D 781.751 mm²
Which measurement is closest to the area of the cracker in square millimeters?
Responses
A 109.9 mm²109.9 mm²
B 54.95 mm²54.95 mm²
C 961.625 mm²961.625 mm²
D 781.751 mm²
Answers
GPT-4o mini
To find the area of a circle (the shape of the cracker) given the diameter, you can use the formula for the area of a circle:
\[
\text{Area} = \pi r^2
\]
where \( r \) is the radius of the circle. The radius is half of the diameter. Given that the diameter is 35 millimeters, the radius is:
\[
r = \frac{35}{2} = 17.5 \text{ mm}
\]
Now, substitute the radius into the area formula:
\[
\text{Area} = \pi (17.5)^2
\]
\[
\text{Area} = \pi (306.25)
\]
\[
\text{Area} \approx 3.14159 \times 306.25 \approx 962.112 \text{ mm}^2
\]
The closest measurement to the computed area of approximately 962.112 mm² is:
**C. 961.625 mm²**.
\[
\text{Area} = \pi r^2
\]
where \( r \) is the radius of the circle. The radius is half of the diameter. Given that the diameter is 35 millimeters, the radius is:
\[
r = \frac{35}{2} = 17.5 \text{ mm}
\]
Now, substitute the radius into the area formula:
\[
\text{Area} = \pi (17.5)^2
\]
\[
\text{Area} = \pi (306.25)
\]
\[
\text{Area} \approx 3.14159 \times 306.25 \approx 962.112 \text{ mm}^2
\]
The closest measurement to the computed area of approximately 962.112 mm² is:
**C. 961.625 mm²**.