Question

The diameter of the cracker shown is 35 millimeters.

35 mm

Which measurement is closest to the area of the cracker in square millimeters?
Responses
A 109.9 mm²
B 54.95 mm²
C 961.625 mm²
D 781.751 mm²

Answer 1

To find the area of the cracker, which is circular, we can use the formula for the area of a circle:

\[
A = \pi r^2
\]

where \( r \) is the radius of the circle. The radius is half of the diameter. Given the diameter is 35 mm, the radius will be:

\[
r = \frac{35 \text{ mm}}{2} = 17.5 \text{ mm}
\]

Now we can calculate the area:

\[
A = \pi (17.5 \text{ mm})^2
\]

Calculating \( (17.5 \text{ mm})^2 \):

\[
(17.5)^2 = 306.25 \text{ mm}^2
\]

Now we multiply by \( \pi \):

\[
A \approx 3.14159 \times 306.25 \approx 962.1125 \text{ mm}^2
\]

Looking at the choices provided and rounding appropriately, the closest answer to 962.1125 mm² is:

**C. 961.625 mm²**