To find the area of the cracker, which is circular, we can use the formula for the area of a circle:
\[ A = \pi r^2 \]
where \( r \) is the radius of the circle. The radius is half of the diameter. Given the diameter is 35 mm, the radius will be:
\[ r = \frac{35 \text{ mm}}{2} = 17.5 \text{ mm} \]
Now we can calculate the area:
\[ A = \pi (17.5 \text{ mm})^2 \]
Calculating \( (17.5 \text{ mm})^2 \):
\[ (17.5)^2 = 306.25 \text{ mm}^2 \]
Now we multiply by \( \pi \):
\[ A \approx 3.14159 \times 306.25 \approx 962.1125 \text{ mm}^2 \]
Looking at the choices provided and rounding appropriately, the closest answer to 962.1125 mm² is:
C. 961.625 mm²