Question

is (-2,6) a solution to the system of these linear equations x + 2y=10 and 3x + y =0? why?

Answer 1

bot?

Answer 2

To determine whether the point (-2, 6) is a solution to the system of linear equations given by \(x + 2y = 10\) and \(3x + y = 0\), we can substitute the values of \(x\) and \(y\) into both equations and check if they hold true.

1. **Substituting into the first equation \(x + 2y = 10\)**:
\[
(-2) + 2(6) = 10
\]
\[
-2 + 12 = 10
\]
\[
10 = 10 \quad \text{(True)}
\]

2. **Substituting into the second equation \(3x + y = 0\)**:
\[
3(-2) + 6 = 0
\]
\[
-6 + 6 = 0
\]
\[
0 = 0 \quad \text{(True)}
\]

Since both equations are satisfied by the point (-2, 6), we conclude that (-2, 6) is indeed a solution to the system of linear equations.