Asked by aaron
                Determine the vertical asymptotes of the graph of graph of y=secx/logx for x≤2pi
            
            
        Answers
                    Answered by
            Reiny
            
    Vertical asymptotes occur when the denominaotrs of your function equal zero.
y = secx/logx is the same as
y = 1/(cosx logx)
so you would have those asymptotes when
cosx = 0 or logx = 0
x = pi/2 or 3pi/2 or x = 1
    
y = secx/logx is the same as
y = 1/(cosx logx)
so you would have those asymptotes when
cosx = 0 or logx = 0
x = pi/2 or 3pi/2 or x = 1
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