Asked by Help Me Please
Determine the holes, vertical asymptotes and horizontal asymptotes of the
rational function. y=3x^2+10x-8/x^2+7x+12
Can you also show your work. I need to do corrections. I have a 68 I just need to get to a 70. This would mean so much to me if anybody could help. I'm begging here~~~
rational function. y=3x^2+10x-8/x^2+7x+12
Can you also show your work. I need to do corrections. I have a 68 I just need to get to a 70. This would mean so much to me if anybody could help. I'm begging here~~~
Answers
Answered by
Reiny
I am sure you meant
y= (3x^2+10x-8)/(x^2+7x+12 )
= (x+4)(3x-2)/(x+3)(x+4)
= (3x-2)/(x+3)
so you have a vertical asymptotes at x = -3
since we cancelled (x+4)/(x+4) and that would be 0/0 if x = -4
we have a hole at x = -4 , y = -14/-1 or 14, hole at (-4,14)
since the numerator is degree 3 and the denominator of degree 2, there is no vertical asymptote but the functions approaches y = 3x
confirmation by Wolfram:
http://www.wolframalpha.com/input/?i=plot+y%3D+(3x%5E2%2B10x-8)%2F(x%5E2%2B7x%2B12+)
y= (3x^2+10x-8)/(x^2+7x+12 )
= (x+4)(3x-2)/(x+3)(x+4)
= (3x-2)/(x+3)
so you have a vertical asymptotes at x = -3
since we cancelled (x+4)/(x+4) and that would be 0/0 if x = -4
we have a hole at x = -4 , y = -14/-1 or 14, hole at (-4,14)
since the numerator is degree 3 and the denominator of degree 2, there is no vertical asymptote but the functions approaches y = 3x
confirmation by Wolfram:
http://www.wolframalpha.com/input/?i=plot+y%3D+(3x%5E2%2B10x-8)%2F(x%5E2%2B7x%2B12+)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.