Question

A pea plant with round seeds a (RR) is crossbred with another pea plant with wrinkled seeds (rr). What is the probability of producing offspring with genotype Rr?

Answer 1

In a cross between a pea plant with round seeds (RR) and a pea plant with wrinkled seeds (rr), we can use a simple Punnett square to determine the possible genotypes of the offspring.

- The round seeds (R) are dominant, and the wrinkled seeds (r) are recessive.
- The parent plants are:
- Parent 1: RR (homozygous dominant)
- Parent 2: rr (homozygous recessive)

To create a Punnett square:

\[
\begin{array}{c|c|c}
& R & R \\
\hline
r & Rr & Rr \\
\hline
r & Rr & Rr \\
\end{array}
\]

From the Punnett square, we can see the possible genotypes of the offspring:

- Rr (which has round seeds) appears in all 4 outcomes.

So, the probability of producing offspring with the genotype Rr is 100% (or 1). All offspring will have the genotype Rr.