Question

A pea plant with round seeds (RR) is crossbred with another pea plant with wrinkled seeds (rr). What is the probability of the offspring having wrinkled seeds?

Group of answer choices

75%

0%

50%

25%

Answer 1

In the cross between a pea plant with round seeds (RR) and another with wrinkled seeds (rr), you can set up a simple Punnett square to determine the genotypic and phenotypic ratios of the offspring.

**Parent Genotypes:**
- Round seeds (RR) - homozygous dominant
- Wrinkled seeds (rr) - homozygous recessive

**Cross: RR x rr**

The gametes from the round seeds parent (RR) will be R (two entry options):
- R
- R

The gametes from the wrinkled seeds parent (rr) will be r (two entry options):
- r
- r

**Punnett Square:**

| | R | R |
|-------|-----|-----|
| **r** | Rr | Rr |
| **r** | Rr | Rr |

**Resulting Genotypes:**
- All offspring will have the genotype Rr, which means they are all heterozygous.

**Phenotypes:**
- Round seeds are dominant (R), and wrinkled seeds are recessive (r).
- Therefore, all offspring (100%) will express the round seed phenotype.

Thus, the probability of the offspring having wrinkled seeds (rr) is **0%**.

The correct answer is: **0%**.