To compare the amounts of liquid in the two vats over time, we can set up an equation based on the information provided.
Let's define \( x \) as the time in minutes.
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For the first vat (which starts empty and fills at 6 gallons per minute): \[ \text{Amount in first vat} = 6x \]
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For the second vat (which starts with 10 gallons and fills at 4 gallons per minute): \[ \text{Amount in second vat} = 10 + 4x \]
Now, to find out when both vats have an equal amount of liquid, we set these two expressions equal to each other:
\[ 6x = 10 + 4x \]
Thus, the equation to represent the situation is:
\[ 6x = 10 + 4x \]