Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vate already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. when will the two vats have the amount of liquid

they will have the same amount of liquid after ___ minutes.

1 answer

To find the time at which the two vats will have the same amount of liquid, we need to set up an equation.

Let t be the number of minutes that have passed.
The amount of liquid in the first vat after t minutes is given by 6t, as it is filling at a rate of 6 gallons per minute.
The amount of liquid in the second vat after t minutes is given by 28 + 4t, as it initially had 28 gallons and is filling at a rate of 4 gallons per minute.

To find the time at which the two vats have the same amount of liquid, we set up the equation: 6t = 28 + 4t.

Simplifying the equation, we get:
6t - 4t = 28
2t = 28
t = 28/2
t = 14

Therefore, the two vats will have the same amount of liquid after 14 minutes.