To find the time at which the two vats will have the same amount of liquid, we need to set up an equation.
Let t be the number of minutes that have passed.
The amount of liquid in the first vat after t minutes is given by 6t, as it is filling at a rate of 6 gallons per minute.
The amount of liquid in the second vat after t minutes is given by 28 + 4t, as it initially had 28 gallons and is filling at a rate of 4 gallons per minute.
To find the time at which the two vats have the same amount of liquid, we set up the equation: 6t = 28 + 4t.
Simplifying the equation, we get:
6t - 4t = 28
2t = 28
t = 28/2
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes.
Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vate already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. when will the two vats have the amount of liquid
they will have the same amount of liquid after ___ minutes.
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