Given point A(2,4) on the triangle in Quadrant I, where is the new point if the triangle is rotated 90 degrees counterclockwise? (1 point) (-4,-2) (4,-2) (-2,-4) (-4,2)

Answer 1

To rotate a point 90 degrees counterclockwise around the origin, you can use the transformation:

\[ (x, y) \rightarrow (-y, x) \]

For point A(2, 4):

1. Replace \(x\) and \(y\) with their values:

   • \(x = 2\)
   • \(y = 4\)

2. Apply the transformation:

   • New x-coordinate: \(-y = -4\)
   • New y-coordinate: \(x = 2\)

So, the new point after the rotation is \((-4, 2)\).

Thus, the new point is \((-4, 2)\).