Given point A(2,4) on the triangle in Quadrant I, where is the new point if the triangle is rotated 90 degrees counterclockwise? (1 point) (-4,-2) (4,-2) (-2,-4) (-4,2)

Answer 1

To rotate a point 90 degrees counterclockwise around the origin, you can use the transformation:

$$(x,y)\to (-y,x)$$

For point A(2, 4):

1. Replace $x$ and $y$ with their values:

   • $x=2$
   • $y=4$

2. Apply the transformation:

   • New x-coordinate: $-y=-4$
   • New y-coordinate: $x=2$

So, the new point after the rotation is $(-4,2)$.

Thus, the new point is $(-4,2)$.