Square ABCD

has vertices point A(1, −3)
, point B(4, −3)
, point C(4, −1)
, and point D(1, −1)
. Find the coordinates of A′
, B′
, C′
, and D′
after a dilation with a scale factor of 5 and a center point of dilation at the origin.(1 point)
Responses

A′(5, −15)
, B′ (20, −15)
, C′ (20, −5)
, and D′(5, −5)
A′(5, −15)
, B′ (20, −15)
, C′ (20, −5)
, and D′(5, −5)
- no response given

A′(5, −15)
, B′ (−20, −15)
, C′ (20, −5)
, and D′(5, −5)
A′(5, −15)
, B′ (−20, −15)
, C′ (20, −5)
, and D′(5, −5)
- incorrect

A′(−5, −15)
, B′ (20, −15)
, C′ (20, −5)
, and D′(5, −5)
A′(−5, −15)
, B′ (20, −15)
, C′ (20, −5)
, and D′(5, −5)
- no response given

A′(5, −15)
, B′ (20, −15)
, C′ (20, −5)
, and D′(−5, −5)
A′(5, −15)
, B′ (20, −15)
, C′ (20, −5)
, and D′(−5, −5)
- no response given
Remaining Attempts : 1

1 answer

To find the coordinates of the points A′, B′, C′, and D′ after a dilation with a scale factor of 5 and a center of dilation at the origin, we can use the formula for dilation:

\[ (x', y') = (kx, ky) \]

where \( (x, y) \) are the original coordinates, \( (x', y') \) are the dilated coordinates, and \( k \) is the scale factor.

Given a scale factor of \( k = 5 \):

  1. For point A(1, -3): \[ A' = (5 \times 1, 5 \times -3) = (5, -15) \]

  2. For point B(4, -3): \[ B' = (5 \times 4, 5 \times -3) = (20, -15) \]

  3. For point C(4, -1): \[ C' = (5 \times 4, 5 \times -1) = (20, -5) \]

  4. For point D(1, -1): \[ D' = (5 \times 1, 5 \times -1) = (5, -5) \]

After performing the calculations, we find the new coordinates:

  • A′(5, -15)
  • B′(20, -15)
  • C′(20, -5)
  • D′(5, -5)

Thus, the correct answer is:

A′(5, −15), B′(20, −15), C′(20, −5), and D′(5, −5).

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