Asked by Candice

Let ABCD be a square with side legnth 7cm. Another square KLMN is inscribed into ABCD such that its vertices lie on the sides of ABCD.
Find the lenghts of parts of ABCD sides which are divided by the vertices of KLMN. If [the area of KLMN]: [area of ABCD] = 25:49
Answered by Reiny
you will have 4 congruent triangles.
each will have legs of x and 7-x and a hypotenuse of 5
thus x^2 + (7-x)^2 = 25

solve as a quadratic, it factors nicely, and you should have sides of 3 and 4
Answered by Bob
How would you know that the hypotenuse is length 5? Does it have something to do with the ratio?
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