Question

How many times larger is  9×10^−8 than  3×10^−12 ?(1 point)Responses3×1043 times 10 to the 4th power6×10−36 times 10 to the negative 3 power3×1033 times 10 cubed6×10−4

Answer 1

To determine how many times larger \( 9 \times 10^{-8} \) is than \( 3 \times 10^{-12} \), we can divide the two numbers:

\[
\frac{9 \times 10^{-8}}{3 \times 10^{-12}} = \frac{9}{3} \times \frac{10^{-8}}{10^{-12}}
\]

Calculating each part:

1. \( \frac{9}{3} = 3 \)
2. \( \frac{10^{-8}}{10^{-12}} = 10^{-8 - (-12)} = 10^{-8 + 12} = 10^{4} \)

Now combine the results:

\[
3 \times 10^{4}
\]

So, \( 9 \times 10^{-8} \) is \( 3 \times 10^{4} \) times larger than \( 3 \times 10^{-12} \).

Thus, the correct answer is:

**3×10^4**.