Question

How many times larger is 9×10−8
than 3×10−12
?(1 point)
Responses

6×10−3
6 times 10 to the negative 3 power

3×104
3 times 10 to the 4th power

3×103
3 times 10 cubed

6×10−4

Answer 1

To find how many times larger \(9 \times 10^{-8}\) is than \(3 \times 10^{-12}\), you divide the two values:

\[
\frac{9 \times 10^{-8}}{3 \times 10^{-12}}
\]

This can be simplified as follows:

1. Divide the coefficients:
\[
\frac{9}{3} = 3
\]

2. Subtract the exponents of 10:
\[
\frac{10^{-8}}{10^{-12}} = 10^{-8 - (-12)} = 10^{-8 + 12} = 10^{4}
\]

Putting it all together:
\[
\frac{9 \times 10^{-8}}{3 \times 10^{-12}} = 3 \times 10^{4}
\]

Thus, \(9 \times 10^{-8}\) is \(3 \times 10^{4}\) times larger than \(3 \times 10^{-12}\).

The correct response is:

**3×10^4** (3 times 10 to the 4th power).