To determine how many times larger \(9 \times 10^{-8}\) is than \(3 \times 10^{-12}\), you can divide the two values:
\[ \frac{9 \times 10^{-8}}{3 \times 10^{-12}} \]
This can be simplified as follows:
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Divide the coefficients: \[ \frac{9}{3} = 3 \]
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Divide the powers of ten: \[ \frac{10^{-8}}{10^{-12}} = 10^{-8 - (-12)} = 10^{-8 + 12} = 10^{4} \]
Putting it all together: \[ 3 \times 10^4 \]
Therefore, \(9 \times 10^{-8}\) is \(3 \times 10^{4}\) times larger than \(3 \times 10^{-12}\).
The correct answer is:
\[ 3 \times 10^{4} \]