Question

How many times larger is 9×10^−8 than 3×10^−12 ?(1 point)
Responses

6×10^−4
6 times 10 to the negative 4 power

6×10^−3
6 times 10 to the negative 3 power

3×10^4
3 times 10 to the 4th power

3×10^3

Answer 1

To find out how many times larger \(9 \times 10^{-8}\) is than \(3 \times 10^{-12}\), we can divide the two numbers:

\[
\frac{9 \times 10^{-8}}{3 \times 10^{-12}}
\]

This can be simplified by separating the coefficients and the powers of 10:

\[
\frac{9}{3} \times \frac{10^{-8}}{10^{-12}}
\]

Calculating the coefficients:

\[
\frac{9}{3} = 3
\]

Calculating the powers of 10:

\[
\frac{10^{-8}}{10^{-12}} = 10^{-8 - (-12)} = 10^{-8 + 12} = 10^{4}
\]

Combining both results, we have:

\[
3 \times 10^{4}
\]

Thus, \(9 \times 10^{-8}\) is \(3 \times 10^{4}\) times larger than \(3 \times 10^{-12}\).

So the answer is:

**3×10^4 (3 times 10 to the 4th power)**.