Asked by Kate
                Ok so I kind of forgot how to do this so I looked up on the internet and was told divide the coefficent in the numerator of the highest degree by the highest coeficent of the highest degree in the numerator and that should be your horizontal asymptote 
one problem
f(x) = (x^2 -4)/(x^2 - x - 12)
the coefficents are one in the numerator and one in the denomenator so the horizontal asymptote should be 1 but its not as f(-8) is exactly one so... what's up with that?
            
        one problem
f(x) = (x^2 -4)/(x^2 - x - 12)
the coefficents are one in the numerator and one in the denomenator so the horizontal asymptote should be 1 but its not as f(-8) is exactly one so... what's up with that?
Answers
                    Answered by
            bobpursley
            
    The horizontal asym is 1.  It crosses the asymtote two times.  find f(100)
    
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