Question
A circle has radius of 6 ft. find the area of a sector if θ = 150. leave your answer in terms of pi
Answers
GPT-4o mini
To find the area of a sector of a circle, you can use the formula:
\[
\text{Area of a sector} = \frac{\theta}{360^\circ} \times \pi r^2
\]
Where:
- \(\theta\) is the angle in degrees,
- \(r\) is the radius of the circle.
Given:
- \(r = 6\) ft,
- \(\theta = 150^\circ\).
Now, plug the values into the formula:
\[
\text{Area of a sector} = \frac{150}{360} \times \pi (6^2)
\]
Calculating \(6^2\):
\[
6^2 = 36
\]
Now substitute this value back into the formula:
\[
\text{Area of a sector} = \frac{150}{360} \times \pi \times 36
\]
Next, simplify \(\frac{150}{360}\):
\[
\frac{150}{360} = \frac{15}{36} = \frac{5}{12}
\]
Putting it all together:
\[
\text{Area of a sector} = \frac{5}{12} \times \pi \times 36
\]
Now multiply \(\frac{5}{12}\) by \(36\):
\[
\frac{5 \times 36}{12} = \frac{180}{12} = 15
\]
Thus, the area of the sector is:
\[
\text{Area of a sector} = 15\pi \text{ ft}^2
\]
Therefore, the area of the sector is \(\boxed{15\pi}\) ft².
\[
\text{Area of a sector} = \frac{\theta}{360^\circ} \times \pi r^2
\]
Where:
- \(\theta\) is the angle in degrees,
- \(r\) is the radius of the circle.
Given:
- \(r = 6\) ft,
- \(\theta = 150^\circ\).
Now, plug the values into the formula:
\[
\text{Area of a sector} = \frac{150}{360} \times \pi (6^2)
\]
Calculating \(6^2\):
\[
6^2 = 36
\]
Now substitute this value back into the formula:
\[
\text{Area of a sector} = \frac{150}{360} \times \pi \times 36
\]
Next, simplify \(\frac{150}{360}\):
\[
\frac{150}{360} = \frac{15}{36} = \frac{5}{12}
\]
Putting it all together:
\[
\text{Area of a sector} = \frac{5}{12} \times \pi \times 36
\]
Now multiply \(\frac{5}{12}\) by \(36\):
\[
\frac{5 \times 36}{12} = \frac{180}{12} = 15
\]
Thus, the area of the sector is:
\[
\text{Area of a sector} = 15\pi \text{ ft}^2
\]
Therefore, the area of the sector is \(\boxed{15\pi}\) ft².