Asked by Favour
                A sector of a circle of radius 9cm subtends angle 120 degree at the circle. Find the area of the sector.
SOLUTION
radius=9cm
pie=22/7
titer=120
Area of sector=titer/360 x pie radius square.
=120/360 x 22/7 x 9square
=120/360 x 22/7 x 81
(Zero cancel zero)
=12/36 x 1782/7
=21384/252
=84.8(approximately)
A sector of a circle of radius 9cm subtends angle 120 degree at the circle. Find the area of the sector.
                    
            
            
        SOLUTION
radius=9cm
pie=22/7
titer=120
Area of sector=titer/360 x pie radius square.
=120/360 x 22/7 x 9square
=120/360 x 22/7 x 81
(Zero cancel zero)
=12/36 x 1782/7
=21384/252
=84.8(approximately)
A sector of a circle of radius 9cm subtends angle 120 degree at the circle. Find the area of the sector.
Answers
                    Answered by
            oobleck
            
    titer? where ever did you get that?
The Greek letter θ is <u>theta</u>
oh, and π is <u>pi</u>, not pie!
    
The Greek letter θ is <u>theta</u>
oh, and π is <u>pi</u>, not pie!
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